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can someone help me code this one in python

1. Ask the user to enter a 6-digit number. Ex. 123456 2. Remove the last digit of the entered number. Ex. Removing the last digit from 123456 returns 12345. 3. Divide the new 5-digit number by 7 and check if its remainder is equivalent to the removed digit in Step 2. Ex. The remainder from dividing 12345 by 7 is 4. The removed digit is 6. Hence, they are not equal. 4. Display the result.

24th May 2021, 12:04 AM
JMC
JMC - avatar
4 odpowiedzi
+ 2
Done... I would only share it if you provide your code attempt, as you must first try by yourself for receiving help to complete your own code before ;P
24th May 2021, 12:25 AM
visph
visph - avatar
+ 2
JMC Here are some steps you need to follow to solve this problem: 1 - write code properly with proper indentation 2 - Take input as string 3 - You have to remove last digit, you can use a[:len(a) - 1] 4 - take last digit from number, you can use a[len(a) - 1::] 5 - get reminder from new 5 digit number using % 7 6 - compare reminder value with removed digit 7 - print valid if both are same otherwise print invalid
24th May 2021, 1:51 AM
A͢J
A͢J - avatar
+ 1
1) you should format correctly your code (new lines and indentation)... write/paste it in a (python) code playground project could help (you can then share the link) ^^ 2) however, your code seems good, except that you stopped after the first validation step (check if only 6 digits)... where is the part of 2nd and 3rd points from your description?
24th May 2021, 12:51 AM
visph
visph - avatar
0
visph while True: num = input("Enter a Number: ") try: numbers = [int(i) for i in num] if len(numbers) == 6: print('valid') numbers = numbers[:5] print(numbers) else: print('invalid') except ValueError: print('only numbers')
24th May 2021, 12:37 AM
JMC
JMC - avatar