You are making a program for a bus service. A bus can transport 50 passengers at once. Given the number of passengers waitin

Question

Help

Answer 1

Djebbar Walid ,

before we are going to help you, please present your attempt here. if you haven't done a try by yourself so far, please do so. create your code in playground and post the link to it here.
please also provide a proper task description with sample of input and output.

thanks!

Answer 2

I'm afraid just saying 'help' without giving any code to go with it won't help much but I'll try.

Assuming all buses carry a maximum of 50 passengers at any one time.

const int max_passengers = 50;

// assume that there are n number of people waiting at a bus stop
int waiting = n; //n being how many people are waiting
if (waiting <= max_passengers){int free_seats = max_passengers-waiting; Console.WriteLine("There are " + Convert.ToString(free_seats) + " seats left");}

else if (waiting > max_passengers){int wait = waiting-max_passengers; Console.WriteLine(Convert.ToString(wait) + "people are waiting for another bus to arrive");}

I hope that helps 🙂

Answer 3

Zak Polley thanks bro😊

Answer 4

#include <iostream>
using namespace std;

int main() {

int x,y,z,i;

//x is the number of total passengers a bus can transport
x=50;

//y is the number of total passengers waiting in the bus station
cin >> y;

if (y<x);
{i=x-y;
}

if (y>x);
{z=y%x;
//z is the number of passengers left
i=x-z;
}

//seats left empty
cout << i;

return 0;
}

Answer 5

Thanks bro

Answer 6

If the question is to get how many people will be on the last bus then
Console.WriteLine(passengers%50)

Answer 7

The problem is this task appears before the introducation of if, while etc.