Text Decompressor

Question

You need to decompress text. The compressed version has a number next to each symbol/letter, representing the amount of time that symbol should appear.
For example, a2b3 is the compressed version of aabbb

Task:
Write a program that takes the compressed text as input and outputs the decompressed version.

Input Format:
A single string with letters/symbols, each followed by a number.

Output Format:
A string, representing the decompressed text.

Sample Input:
k2&4b1

from itertools import *
a = input()
b = list(a)
c = []
while len(a)/2 > len(c):
c.append(2)
Output = [b[x - y: x] for x, y in zip(

accumulate(c), c)]
n = 0
z = []
while len(z) < len(Output):
for i in Output:
if Output.index(i) == n:
z.append(i[0] * int(i[1]))
n += 1
df = ("".join(i for i in z))
print(df)

Above my code isn't passing the 5th case and it's locked, hence not able to check it.
Plz help in correcting me.

Answer 1

Swapnil Kamdi ,

i found a way of doing it without itertools. (itertools has great functions, but in this case it can also be done like in the demonstrated code)

inp = "k2&14b1"
char = ''.join([x if not x.isdigit() else ' ' for x in inp]).split()
dig = ''.join([x if x.isdigit() else ' ' for x in inp]).split()
[print(c * int(d), end='') for c,d in zip(char, dig)]

the code is doing:

▪︎a comprehension that takes all "non-digit" characters and puts them in a new list, that will be joined and split again (other chars will output as " ")
▪︎a comprehension that takes all "digit" characters and puts them in a new list, that will be joined and split again (other chars will output as " ")
▪︎a comprehension that uses zip with 2 generated lists and outputs the final result

Answer 2

n = input()
print( "".join([i*int(x) for i,x in zip(n[0::2],n[1::2])]))

Answer 3

This one work too:
txt = input()
tab = list(txt)
for i in range(0,len(tab),2):
print(tab[i]*int(tab[i+1]),end="")

Answer 4

or maybe that your code produce an error for input where numbers are greater than 9:

k21&4b1

Answer 5

Vasiliy
Plz FYI.

https://www.sololearn.com/coach/85?ref=app

Answer 6

Shortest and easiest way to get it done:

compressed_string = input()

decompressed_string = " "
for i in compressed_string:
if not i.isdigit():
decompressed_string += i * int(compressed_string[(compressed_string.index(i)+1)])

print(decompressed_string)

Answer 7

def decompress(x):
symbol = x[::2]
mult = x[1::2]
decompress = [i*int(j) for i,j in zip(symbol,mult)]

print(''.join(decompress))

decompress(input())

Answer 8

That works and is short ->

str = list(input())
for i in range(0,len(str),2):
print(str[i]*int(str[i+1]),end="")

Hope it helps!

Answer 9

word=str(input())
l=[w for w in word]
n=l[1::2]
c=l[::2]
d=[int(v) for v in n]
result=[x*y for x,y in zip(c,d)]
print("".join(result[0::]))

Answer 10

visph Vasiliy Maybe need to take the separate integars first within list. Could you plz bother to help me with code.

Answer 11

loop over the char of the string, store the first, got the number while it's a digit (accumulate as a string), when a no digit occur (or end of string), use the stored char and the number to add to your result string... then if not end of string store the new char occuring ;)

Answer 12

Specify from which section this test

Answer 13

This is not available to me, since I am not a pro.
These tasks are given in accordance with the passed material. I need to know the topic of the chapter in order to correctly solve this task.

Answer 14

This works great too 😊

i = list(input())
ns = ""

for x in range(len(i))[::2]:
ns += (i[x] * int(i[x+1]))

print(ns)

Answer 15

decompressor = input()
decomp = list(decompressor)

x=[]
y=[]

for i in decomp:
if i.isnumeric():
x.append(int(i))
else:
y.append(i)

text=''

for n in range(0,len(x)):
text += (x[n]*y[n])

print(text)

An alternative to some of the solutions above.

Answer 16

Maybe the problem is that you do not have a condition when writing a number at the beginning of a line?

Example:
5k2&4b1

Answer 17

string_input = input()
first = []
second = []
i: str
for i in string_input:
if not i.isdigit():
second.append(i)
else:
first.append(i)
first = [int(i) for i in first]

def multipl(list1, list2):
first_second = [] # Create empty list
for x in range(0, len(list1)):
first_second.append(list1[x] * list2[x]) # Adds each element to the list
return print(''.join(first_second))

multipl(first, second)

Answer 18

This the code I figured out