Random unwanted number printed.

Question

I am trying to complete a challenge that I think I understand. However, after running the code, the answer is incorrect since an extra number prints, the number 1, it's making it wrong for all cases.

Answer 1

I think you should swap a and b in output done inside 'printOrder' function, and remove the 'cout' line in your 'main' function ^^

Answer 2

what is the purpose of your line:

cout << printOrder << endl;

???

Answer 3

Thanks! I had figured it out right before see your reply .

Answer 4

#include <iostream>
#include <string>
using namespace std;

//complete the function with one default arg:ument
void printOrder(string a, string b = "Black tea") {
cout << b << "\n";
cout << a << "\n";
}

int main() {
//getting coffee type
string friendOrder;
cin >> friendOrder;

printOrder(friendOrder);

return 0;
}

Answer 5

I just remembered that i dont have to print printOrder because that's the literal purpose of the function 😂 i didn't want to let it do it's job . Also I'm assuming since i did print it, that's where the 1 came from. I'm so tired I was thinking too hard.

I guess this is why we debug 😂

Answer 6

#include <iostream>
#include <string>
using namespace std;

//complete the function with one default arg:ument
void printOrder(string a, string b = "Black tea") {
cout << a << "\n";
cout << b << "\n";
}

int main() {
//getting coffee type
string friendOrder;
cin >> friendOrder;

printOrder(friendOrder);

cout << printOrder << endl;

return 0;
}

Answer 7

Your usual order at your favorite cafe is black tea, which the waiter brings you by default. Today, however, you are with your friend and it is his first time there. Obtain your friend's order in one word as input, and place the order for both of you. Complete the function so that it will output "Black tea" by default (without an argument) and then your friend's order as an argument.

Sample Input
Americano

Sample Output
Black tea
Americano