Why this break statement not work?

Question

In this code break statement not in loop why?
And when it is in loop i want to print only "yes"
but why it prints "None" also?

https://code.sololearn.com/cee5TGEAD6Ef/?ref=app

Answer 1

Aayush Jat If you haven't a loop you can't use "break" or "continue" keywords.

Instead you can use "pass" (or "return" if you are inside a function) to have in part the same behaviour

Try with

def search(text,word):
if word in text:
return "yes"
return

def search(text,word):
if word in text:
return "yes"

def search(text,word):
if word in text:
return "yes"
else:
pass

def search(text,word):
if word in text:
print("yes")

and so on...

Answer 2

Where is the loop in your code ?

Answer 3

None is printed as it is the return value of your function, and you print the result of its call in addition to printing 'yes' inside the function ^^

break only work in loop and if line is reached (inside an if..else statement, it depend of the condition where it is ;P