0
Python regex that will match anything that isn't a alphabet letter.
4 odpowiedzi
+ 3
^a-zA-Z
+ 1
your attempt?
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Rellot's screwdriver
I wrote this
Import re
old_str = "da8v+i4d"
pattern = r'[0-9]'
new_str = re.sub(pattern, '', old_str)
print(new_str[::-1])
#that will match all numbers and replace them with an empty string, then Reverse the string right.
#but i also want it to match the special symbols
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Bibek Oli is almost right, except he doesn't explicitly explain than its code should replace your 0-9 character range inside square brackets of your pattern ;)
the ^ (carret) at start of a character range is not negate it, so will match any character that are NOT listed after, rather than matching those wich are listed
however, you could make your regex replacement a few more efficient, by appending a + operator quantifier after the closing bracket: this will match one to any number of characters defined by the range, and so replace contiguous ones at once instead of replacing each one at a time ;P
pattern = '[^a-zA-Z]'
r before string is not required, as there's no ambiguous character in your regexp (antislashes), but may be put anyway (r doesn'r stand for regexp string but for raw string: doesn't use escape codes)
also, by using case insensitive modifier to your regexp, you could short a few the raw string ^^