What is the output plzz explain too

Question

Int tot=0,i;
for(int i=0; i<10;i++)
{
tot=tot+1;
}printf("%d", tot);

Answer 1

At every iteration it is increasing the value of tot by 1 and the ending point of the condition is 9,so the answer of 10. If you don't understand please complete the course to know about it

Answer 2

#include <stdio.h>

int main() {
//What is the output plzz explain too

int tot=0,i;
for(i=0; i<10;i++)
{
tot=tot+1;
}printf("%d", tot);
return 0;
}
//This is the correct code

Answer 3

Code:

#include <stdio.h>
int main()
{
int tot = 0 , i ;
for(i=0; i<10; i++)
{
tot = tot + 1;
}printf("%d", tot);
return 0;
}

In the code a for loop is used . The loop would iterate until the condition ( i < 10) is false .

Initially tot = 0 , for each iteration one value is added to 'tot'
( tot = tot + 1 )

From i = 0 to i<10 i.e 'i' value is from 0 to 9 (10 values)

The loop iterates 10 times and the number of times 1 is added to the variable 'tot' is 10 .

So the value of the variable 'tot' is 10.

Answer 4

For value of i from 0 to 9 that is 10 times the loop will work and value of total will be 10

Answer 5

Atul then how update the value of tot??

Answer 6

Tot's value is always updated in every iteration

Answer 7

I didn't get but thanks

Answer 8

What doubt you have pls ask?

Answer 9

Already asking read above

Answer 10

I must suggest you to know about the working of loops before solving about this

Answer 11

Output is the sum of all number untill 10 (excluding 10)
In each iteration i is increase by 1 and add to total.

Answer 12

Here int I is declared twice beside all the error coming to the core answer is 10

Answer 13

Output must be 10. Through each iteration total is added 1 to the total.