Just taking numbers from list

Question

list=[1,"appel",2,3,"peach",4,5,"orange",6,"carrot",8,"banana",10,"cat"]
for number in list:
while number<=9:
if (number>2):
print(number)

I just want to see on my output 3,4,5,6,8 these numbers.
Where have i done a mistake?

Answer 1

Something like this?
https://code.sololearn.com/co8Mz7AGf3Jr/?ref=app

Answer 2

Calvin Thomas ,

there are 2 issues in your code sample:

▪︎ isnumeric() is a string function, but numbers in list are integers
▪︎ the result of the code is 1,2,3,4,5,6,8,10 but should be 3,4,5,6,8

Answer 3

Remove the while loop, unindent your if statement and print statement... it should work

Answer 4

The while loop makes no sense. Its exit condition depends on a variable which doesn't change inside the loop, so it either runs once or it runs forever.
There's no filter to check only numbers.

Things to learn that will help you a lot here:
- break and continue statements - You can end a loop or skip an iteration at arbitrary conditions
- List comprehensions - You can create a new list by filtering an existing one
- join function - Easily formats lists, which helps printing them

Answer 5

What is the need of while loop there in for loop . it loops forever. Just use a if condition instead.
And you can check condition like
if type(number) == int :

Answer 6

Habib Here's a possible solution:

print(*filter(lambda x: x.isnumeric(), list), sep=',')

# Hope this helps