Can anyone explain to me why the output in this code is [6,6,6,6]

Question

First I would be happy if someone could explain to me the output of this line of code "return[lambda x:i*x for i in range(4)]" , then last one , bringing this output [6,6,6,6] .

#Codes
def multiplier():
return[lambda x:i*x for i in range(4)]
print ([m(2) for m in multiplier()])

Answer 1

Emmanuel Massawe ,

the function you are using is returning a lambda object. i am not sure what you want to achieve with this, or if it comes by accident.

if you just want to take a number from a range and multiply it by an other number, you could do:

def multiplier():
return [i*2 for i in range(4)]

print(multiplier()) # result is [0,2,4,6]

if you have a different intent, please give a description what you want to achieve.
thanks!

Answer 2

multiplier() return an array (comprehension) wich contains 4 times the lambda x: i*x

so your code (I guess it comes from a challenge) is equivalent to:

mult = [
lambda x: i*x,
lambda x: i*x,
lambda x: i*x,
lambda x: i*x,
]
print([m(2) for m in mult])

the print print the array (comprehension) of each function returning last value of i (3) multplied by argument given (2)