What is wrong with my code

Question

numbers =list(range(1000))
odd_numbers=[ ]
even_numbers=[ ]
for x in numbers:
if ( x%3==0):
odd_numbers.append(x)
else:
even_numbers.append(x)
print (list(odd_numbers))
print (list(even_numbers))

Answer 1

Yusuf Jamal

numbers =list(range(1000))
odd_numbers=[ ]
even_numbers=[ ]
for x in numbers:
if ( x%2!=0):
odd_numbers.append(x)
else:
even_numbers.append(x)

print(odd_numbers)
print(even_numbers)

Answer 2

Yusuf Jamal
Mistakes in your code,
1)x%3==0

This statement means if x is only divisible by 3.Not means x is odd. x%2!=0 means x is not divisible by 2 . So it takes odd numbers. But if you use x%2==0 it takes only a even numbers.

2)list(odd_numbers)

You have already created a list .
So, there is no use to use list() function.

Answer 3

Well you can also do like this - https://code.sololearn.com/c1A2I4JA2Q82/?ref=app

Answer 4

Hi Yusuf Jamal ,

Please show us your code! Then only we can help you!

Stick your code!

Answer 5

Print statement is inside the loop, that's why it is printing multiple list

Answer 6

Yusuf Jamal
where is your code?

Answer 7

numbers =list(range(1000))
odd_numbers=[ ]
even_numbers=[ ]
for x in numbers:
if ( x%3==0):
odd_numbers.append(x)
else:
even_numbers.append(x)
print (list(odd_numbers))
print (list(even_numbers

Answer 8

Correct!
Why is it returning multiple list before?

Answer 9

Oh! Thanks

Answer 10

Thank you!

Answer 11

https://code.sololearn.com/cA0A902A0A6A
numbers =list(range(1000))
odd_numbers=[ ]
even_numbers=[ ]
for x in numbers:
if ( x%2!=0):
odd_numbers.append(x)
else:
even_numbers.append(x)
print (list(odd_numbers))
print (list(even_numbers))