Lottery problem

Question

I wanted a program that has two given integers. If all the 3digits of a given number is the same as the second inputted number, then print "Win"; else, print "Nah".

Ex1:
Input: 222 2
Output: Win

Ex2:
Input: 515 5
Output: Nah

Ex3:
Input: 888 8
Output: Win

I need help. I absolutely have no idea how to do this.

I did a little coding, but it only chooses the most occurring number:
https://code.sololearn.com/cA100a6A15a2

Answer 1

Input should see as follows:
7
777

https://code.sololearn.com/c5KtsGlNbvbr/?ref=app

Answer 2

Brianna
You are doing logically correct but taking number in reverse. First is 3 digit number next is single digit number as you specified in description...
Next compare it if result is 3 or not. If result==3 ,print Win else print Nah....

you can simply this with (digit*10+digit)*10+digit == integer ? "Win" :"Nah"

Answer 3

Good job, Brianna. You just lacked control over result. Now write better. No m, no result, a boolean and less code Something as

import java.util.Scanner;
class Main{
public static void main (String args[]){
Scanner input = new Scanner (System.in);
boolean win=true;

int digit = input.nextInt();
int integer = input.nextInt();

for(;win && integer>0;integer/=10)
win=(integer%10)==digit;

System.out.println((win)?"win":"nah");
}
}

if you prefer the whole first and then the single digit just swap the two nextInt

you could also delete the boolean, but you lose in readability

Answer 4

Like this

import java.util.Scanner;
class Main{
public static void main (String args[]){
Scanner input = new Scanner (System.in);

int d = input.nextInt();
int i = input.nextInt();

for(;i%10==d && i>0;i/=10);

System.out.println((i>0)?"win":"nah");

}
}

Answer 5

obviously 0 is not allowed

do you need 0 allowed in the integer?