I need to give input twice to get output, where do i need to fix the code?I need to find the count and sum of given number 1 inp

Question

#include <stdio.h>
int main() {
long long n;
int j,count = 0,sum=0;
printf("Enter Value: ");
scanf("%lld %d", &n,&j);

while (n != 0) {

n /= 10;
++count;

sum+=j%10;
j=j/10;
}

printf("Count: %d sum: %d", count,sum);
}

Answer 1

Give me input example and expected output for testing.

Answer 2

Ipang
Sample input
input: 12
output: Count:2, Sum:3
Input:2673
Output: Count:4, Sum:18

Answer 3

Why input only one number? I see the code reads value for <n> and <j>.

Answer 4

Do you want to write code to take single input and work on it for same result?
If yes, then You can take single input n and copy to j.
scanf("%lld",&n);
long long j=n;

But you can do same with single variable. No need of j, Think about it.. hope it helps...

Answer 5

I get it now, you want to have such output with only one input number. Before I didn't understand cause your thread title wasn't complete. It is possible ...

#include <stdio.h>

int main()
{
long long n, sum = 0, count = 0;

printf( "Enter Value:\n" );
scanf( "%lld", &n );
while ( n )
{
++count;
sum += n % 10;
n /= 10;
}
printf( "Count: %lld sum: %lld", count, sum );
}

You can also take input as string, in which you can escape data type range limits, and can count and sum freely.