Function Series of input

Question

Write a C++ program to take series of numbers as input and give output 1 if even and 0 if odd using functions

Answer 1

not right order in first loop parenthesis:

for (int i=0; i++; i<size)

must be:

for (int i=0; i<size; i++)

not correct operator used in check function:

if (arr[i] / 2==0)

must be:

if (arr[i] % 2==0)

Answer 2

visph sure !! 😅😅🤝

Answer 3

#include <iostream>
using namespace std;
void check (int[],int );
int main()
{ int size;
cout<<" how many numbers you want to enter ? ";
cin>>size ;
int arr[size];
for(int i=0;i++;i<size)
{
cin>>arr[i];

}
check (arr,size);

}
void check (int arr[],int size)

{

for(int i =0;i <size; i++)
if (arr[i] / 2==0)
{
cout<<" 1 "<<endl;
}
else
{
cout<<" 0 "<< endl;
}

}
This was my attempt but it didn't work

Answer 4

Thanks

Answer 5

Finally 😌

#include <iostream>
using namespace std;

void check (int[],int );
int main()
{ int size;
int arr[size];
cout<<" how many numbers you want to enter ? ";
cin>>size;
cout<<"Enter numbers"<<endl;
for(int i=0;i<size;i++)
{

cin>>arr[i];

}
check (arr,size);
return 0;

}
void check (int arr[],int size)

{

for(int i =0;i <size; i++)
if (arr[i] % 2==0)
{
cout<<" 1 "<<endl;
}
else
{
cout<<" 0 "<< endl;
}

}

Answer 6

Guru patel don't mark your own answer as best: it's not true and it's unfair (I give you the corrections to be done) and it will not give you any xp ^^

Answer 7

2==0