Could i done it simplier?

Question

Array problem "What s my discount":

Solved it like this:

#include <iostream>
using namespace std;

int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};

//your code goes here
int discount;
cin >> discount;
for ( int x = 0; x < 11 ; x++ ){
items[x] = items[x] - items[x] * discount / 100;
cout << items[x] << " ";
}

return 0;
}

Was there a way to write the: (items[x] = items[x] - items[x] * discount / 100; ) simplier?

Answer 1

item[x] -= item[x] * discount / 100;

Answer 2

You can go ahead and leave it as someone else may run into the same issue :)

Answer 3

or even:

item[x] *= 1 - discount / 100;

Answer 4

Interesting way of doing it, thx guys, should i delete the post after i get it solved?