Java problem

Question

Scanner in = new Scanner(System.in);
Double num1 = in.nextDouble();
Double num2 = in.nextDouble();
double sum;
sum=num1 + num2;
System.out.println(sum);

If num1 & num2 are interger it'd run fine
Else num1or num2 are double it'd printout error
HELP

Answer 1

What error are you getting? Works fine for me.

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
Double num1 = in.nextDouble();
Double num2 = in.nextDouble();
double sum;
sum=num1 + num2;
System.out.println(sum);
}
}

:::INPUT:::
1
2.3

:::OUTPUT:
3.3

:::INPUT:::
1.5
3

:::OUTPUT:::
4.5

:::INPUT:::
1
2

::::OUTPUT:::
3.0

Answer 2

Can you put it into Code Playground and link me so I can see the error? More than happy to help, just need more information on the error.

Answer 3

Martin Taylor
Thank you it's working
My machine isn't compling because i was using . Instead ,
Thank you
but why is the result use . instead , ??

Answer 4

If your locale uses a comma (,) instead of a period (.) for decimals, then you can change that setting in your JRE so that it reflects your locale instead. That's how the compiler will know which one to expect.

Answer 5

If your system eg Windows has set different separator, because local country habits, installed java expect this sarator instead standard English dot

this shows expected decimal separator

//import java.text.DecimalFormatSymbols;
char dSepar = new DecimalFormatSymbols()
.getDecimalSeparator();
System.out.println( dSepar );

Answer 6

It keeps showing me
Exception in thread "main"
At java base

Answer 7

Your are used
Double num1 = in.nextDouble();
Double num2 = in.nextDouble();
The value shoud be double every time