Why the code2 does not work? SOLVED

Question

#Дан список. Необходимо вывести уникальные элементы списка.
#A list is given. It is necessary to display the unique elements of the list.
Below are 2 solutions for the task. I don't understand why the second code (which is mine) does not work. They seem me the same 🤷

lst1 = [1, 3, 2, 3, 5, 2, 7, 8]

#code1
for i in range(n):
for j in range(n):
if i != j and lst1[i] == lst1[j]:
break
else:
print(lst1[i], end="")
print()

#code2
for i in range(n):
for j in range(i+1, n):
if lst1[i] == lst1[j]:
break
else:
print(lst1[i], end="")

Answer 1

Елена Леващева ,

even if the issue is solved, you may be interested in a code that looks less complex and has a good readability (but it uses function count()):

lst = [1, 3, 2, 3, 5, 2, 7, 8]
for num in lst:
if lst.count(num) == 1:
print(num,end=" ")

Answer 2

In code 2, the inner loop starts at the index after i. So with every iteration of i, you are comparing each number to less and less elements.
When you reach i=3 (value 3) the inner loop only checks index 4 to 7 and does not find the duplicate at index 1

Answer 3

Tibor Santa Thanks a lot. i got it so great

Answer 4

https://code.sololearn.com/crxWCR94g4BQ/?ref=app

Answer 5

Vasiliy thank you very much for showing codes work. It helped a lot.

Answer 6

Lothar thanks a lot for your. Great code. I am certainly interested.