Why it is showing "invalid syntax" or "indentation error"?

Question

x=1
while x<10:
if x%2==0:
print(str(x) + "is even")
else:
print(str(x) +"is odd")
x+=1

Answer 1

#Why it is showing "invalid syntax" or "indentation error"?

x=1
while x<10:
if x%2==0:
print(str(x) + "is even")
else:
print(str(x) +"is odd")
x+=1

Your indentation is wrong try with this code, it's a way to learn how this works

Answer 2

I got It.. worked.. Thank u 👍🏻

Answer 3

because you didn't indent the statement after if and else condition

Answer 4

It should be like this
from if.
if x%2==0:
print(str(x)+"is even")
else:
print(str(x)+"is odd")
...

Answer 5

x += 1
There should be a space between variable name and operator

Answer 6

#try this

x=1
while x<10:
if x%2==0:
print(str(x) + "is even")
else:
print(str(x) +"is odd")
x+=1

Answer 7

I did it on my computer but it still showing the error

Answer 8

Ohh thank u so much 😊

Answer 9

Did it work?

Answer 10

Not yet, now it's showing "invalid syntax" error at else :