How to find vowel in string

Question

word1=input("1st word:")
word2=input("2nd word:")
count=0
if len(word1) > len(word2):
for i in word1:
if i in (A,a,I,i,E,e,O,o,U,u):
count +=1
else:
for i in word2:
if i in (A,a,I,i,E,e,O,o,U,u):
count +=1

print(count)

this is my code. but I am getting an error

Answer 1

text=input()
n=[]
vow='AaEeIiOoUu'
for o in vow:
l=text.count(o)
n.append(l)
print(sum(n))

Answer 2

The letters in the if-statement s need to be a string, for example "A"

Answer 3

word1=input("1st word:")
word2=input("2nd word:")
count=0
if len(word1) > len(word2):
for i in word1:
if i in ('A','a','I','i','E','e','O','o','U','u'):
count +=1
else:
for i in word2:
if i in ('A','a','I','i','E','e','O','o','U','u'):
count +=1

print(count)

Answer 4

below is an example of combining some of the solutions brought up by Imadez , Lisa , and Jay Matthews .

i created a variable that holds the string of vowels and in the if statement i transform each letter to be in lowercase.

# How to find vowel in string

word1=input("1st word:")
word2=input("2nd word:")

# create tuple with vowels
vowels = ("aeiou")
count=0

# count vowels if lowercase letter is in vowels tuple
if len(word1) > len(word2):
for i in word1:
if i.lower() in vowels:
count +=1
else:
for i in word2:
if i.lower() in vowels:
count +=1

print(count)

Answer 5

There are 2 possibles:
1 Look for capitals.
2 Look for small.

If (1) : convert the string to uppercase
If (2) : convert the string to lowercase

Either case make a tuple of characters :

And...

Search for the appropriate character and increment a count variable every time ⏲️.

Answer 6

Gouri Shinde How about this one? :-

print(sum(1 for x in input().lower() if x in "aeiou"))

# Hope this helps