What really happens in this code

Question

How each loop works?
https://code.sololearn.com/c3UBQ5p302ht/?ref=app

Answer 1

Hi alagammai!
Inorder to understand this code, it's better to divide it into two snippets.
1. Without variable j, output pattern would be like this
(for i in range(1,10,2):
print(i*'*')), here i = 1,3,5...
*
***
*****

2. After you added variable j with i times '*', each line of snippet1 is added with j times space hence, j is decreasing in each iteration.
J = 9,8,7,
(spaces) ........*
......***
.....*****

Answer 2

https://code.sololearn.com/cAcU7m0Wri4M/?ref=app

Playing with it is most fun

Answer 3

Okay.
First line: j = 9 (pretty obvious)
Second line: for i in range (1, 10, 2):
This for loop will go from 1 through to 9 in increments of 2 i.e 1, 3, 5, 7, 9.
Third line: print(' ' * j + i * '*')
This is the part that may confuse you. This line prints : "j" spaces, then prints "i" stars. In the first run of the loop, it will print 9 spaces, then 1 star. In the second run, it will print 8 spaces, then 3 stars (j is decremented by 1 after each loop run: j -= 1).... In the last run of the loop it will print 5 spaces and 9 stars.

Answer 4

JUMP_LINK__&&__Python__&&__JUMP_LINK Learner David Akhihiero Calvin Thomas thank you so much

Answer 5

Barnik Roy thank you

Answer 6

Now check the print function carefully now you can understand

j=9
for i in range(1,10,2):
print((' '*j) + (i*'*'))
j-=1

here print function prints stars and spaces with single print function

Answer 7

alagammai uma Just analyze the code by yourself. You'll understand it. Try this:

j = 9
for i in range(1, 10, 2):
print(f"i = {i}, j = {j}\n")
print(" " * j + "*" * i, "\n")
j -= 1

Answer 8

Yes this question is the question In which anyone got confused first time as I am but when you will see it carefully you will got it what is happening in really.
alagammai uma
JUMP_LINK__&&__Python__&&__JUMP_LINK Learner you have explained very correctly.

Answer 9

Narendhar Kothuri thank you