0

Help please, Why does this instruction list have a reverse effect?

newList = [] for n in range(4): newList.insert(0,n + 0) print (newList)

16th Aug 2021, 11:42 AM
Jenkins
2 odpowiedzi
+ 2
Hi Jenkins! It's inserting each element as first element of newList(indices start from 0) in each iteration(0,1,2,3). Inorder to understand this code clearly, you can print the output inside loop. This is what I mentioned above newList = [] for n in range(4): newList.insert(0,n ) print (newList)
16th Aug 2021, 11:48 AM
Python Learner
Python Learner - avatar
+ 1
Jenkins I checked your profile and you have not completed python for begineers course even 1% so first learn it and then try to practice it ! syntax : list.insert(index, element) The insert() function inserts the given element at the specified index. (index starts from 0 ) you are adding each element to the 0th index so others elements will be shifted to right side. newList=[] for n in range(4): newList.insert(0,n) #n+0 = n 1st iteration --> [0] 2nd iteration --> [1,0] # 1 is inserted at index 0th so first element is sifted to right side 3rd iteration ---> [2,1,0] 4th iteration ---> [3,2,1,0] that's why you are getting reversed elements of list ⏺️ Solution 1 : you can simply use append() function to insert element at the end of list. newList=[] for n in range(4): newList.append(n) print(newList) ------------------------------------ OR ⏺️Solution 2 : using insert() itself newList=[] for n in range(4): newList.insert(n,n) print(newList) #Hope this helps !
16th Aug 2021, 12:50 PM
Ratnapal Shende
Ratnapal Shende - avatar