Python: How to Get the Numbers that are Greater/Less Than x in a Tuple

Question

Does anyone know how to get all of the numbers in a tuple that are greater/less than a specific number?
I found this
https://www.sololearn.com/Discuss/1619358/?ref=app
, however, that was only for a specific index.
Example:
x=4,5,6,7,8,9
How would I get the amount of numbers that are greater than 6?
^would be 3
How would I get the numbers from it that are greater than 6?
^would be 7,8,9

Answer 1

You should also note whether or not <x> was sorted (and better when no duplicate items). I guess a different approach may be used for sorted/unsorted container.

Answer 2

✩✮★✮✩ thank you! Could you explain the "*"?

Answer 3

Ipang by sorted do you mean “1,2,3,4,5…” as opposed to “2,5,1,4,3…”?

Answer 4

Yes Katz
That's what I meant by sorted ...

Answer 5

Ipang why should it be noted?

Answer 6

Ipang then greater_than_six would equal all of the values from the tuple that are greater than 6? Or would it be how many are greater than 6?

Answer 7

You see ...
When the tuple contains e.g. 100 values (and sorted sequentially), we can do this for example

greater_than_six = len( x ) - x.index( 6 ) - 1

Answer 8

Katz,
If I'm not miscalculating, it counts how many ...

To get a new list containing only those greater than 6 we can slice <x> like so

print( x[ x.index( 6 + 1 ) : ] )