Please tell me what's happening here T~T

Question

Take a look at my below code.

https://code.sololearn.com/cPMK8lslJ1f7/?ref=app

In this, the function findMin() returns the lowest of two parameters with the type of the lowest parameter. But, how the second output is of type double??? Thank you already :)

Answer 1

Rishi sorry, I'll edit it later

For the same reason it does that in the other case:
operators (such as ?: ) want their argument to be of the same type, to do that they compare the two types and decide which one is "stronger", and than they convert the "weak" one to that type

In your case double is stronger than int, so int gets converted to double and the overall type of the operator is double

Answer 2

decltype is done at compile time,
that means it will never know the values of a and b, and it will consider just their types

What the compiler will see is:
decltype(bool? int : double) in the first case,

and

decltype(bool? double : int) in the second case

both cases will give decltype(double) by the rules of arithmetic conversion

Answer 3

Angelo I think the first and second case are reversed in your comment. How will the compiler give decltype(double) in the second case? (First case in your comment)

Answer 4

Angelo :O that's why my code is behaving so. Thank you, now this is solved for me :)