SyntaxError - but why??

Question

import math
a = float(input()

if type(number) == float:
x = a
print("sin "+x+"° = "math.sin(x))

elif type(number) == int:
x = int(a)
print("sin "+x+"° = "math.sin(x))

Answer 1

JUMP_LINK__&&__Python__&&__JUMP_LINK Learner

Since there is : a = float(input()),
why do you need if and elif block at all ?
The same code can be written in 3 lines:

import math

a = float(input())

print(f"sin{a} = {math.sin(a)}")

You can add exception in second line for string input ..

Correct me if im wrong 😊

Answer 2

Hi Sacar!
Of course, you're correct.
But I was trying to help him in his style specifically, concatenation. The way you mentioned is also used for concatenation.

Answer 3

JUMP_LINK__&&__Python__&&__JUMP_LINK Learner gotcha, bro !

Answer 4

Hi Ferdous!
You let some small mistakes here. One thing is that you have to convert integers to string in concatenation when you're using "+" as concatenation operator but it cannot be used between a string and float. For that, you can use comma instead.
Here it is your working code.
import math
a = float(input())

if type(a) == float:
x = a
print("sin ",x,"° = ",math.sin(x))

elif type(a) == int:
x = int(a)
print("sin ",x,"° = ",math.sin(x))