import re n=input()[::-1] pattern=r"[A-Za-z]" s=re.findall(pattern,n) o=("".join(s)) print (o)

Question

Spy Life Problem (i am stuck here) (needing help)

Answer 1

SoloProg what is different between yours code and Norberto Costa code ??

Answer 2

Simply add the space to the regex.
pattern=r"[A-Za-z ]"

Answer 3

The code has to be decoded word by word(my answer: youaregreat, problem answer: you are great.

Answer 4

Norberto Costa try this
import re

str_ = input()

pattern = r"[^A-Za-z ]"
newstr = re.sub(pattern, "", str_)
print(newstr[::-1])

Answer 5

Norberto Costa spy life task is to flip input value
For example: hello
Output: olleh
2. Hello world
Output: dlrow olleH

Re.sub is used  to remove punctuation and give space
by using your code we are not getting the space for example:
hello world
Output: dlrowolleH ✖️
2. helloworld
Output: dlrowolleH ✔️

Answer 6

Thanks, Hr

Answer 7

Its solved. Thanks

Answer 8

SoloProg have reason

Answer 9

Norberto Costa or...

import re

print(''.join(map(str, re.findall("([a-zA-Z ]*)", input()[::-1]))))

Answer 10

import re
n=input()[::-1]
pattern=r"[A-Za-z]"
s=re.findall(pattern,n)
o=("".join(s))
print (o)

Answer 11

HrCoder your code works. But seriously i do not understand why?

Answer 12

How the method sub knows when to put space?