Last question of the python for beginners 39/39

Question

You’re working on a search engine. Watch your back Google!

The given code takes a text and a word as input and passes them to a function called search().

The search() function should return "Word found" if the word is present in the text, or "Word not found", if it’s not.

Sample Input
"This is awesome"
"awesome"

Sample Output
Word found

Answer 1

https://code.sololearn.com/cOdKzKq2k5oF/?ref=app

Answer 2

Rapmonster Wlcm 😃 but try to solve yourself next exercise...👍

Answer 3

Rapmonster
It must work well. You should enter the text after push enter button then enter the word and submit. Write the inputs,

Input:
for example some text
some
submit
Output:
word found

Try and see. It will work.

Answer 4

text = input()
word = input()

def search(text,word):
if(word in text):
return "Word found"
else:
return "Word not found"

print(search(text, word))

Answer 5

Blocks are the problem

Code:

def search(text,word) :
if word in text :
print ('Word found')
else:
print('Word not found')
text = input()
word = input()
search(text,word)

Answer 6

Rapmonster sorry that's blocks not Bpicks 😋

Answer 7

Rapmonster it should work fine what error are u getting

Answer 8

Some users have reported that they currently have problems with code projects – seems to be a sololearn problem. Try again tomorrow ;)

Answer 9

Vinod Nagda
This link does not seem related to the thread's topic. Please remove it, this is not the right place for advertisement.

Answer 10

#try this code

def search(text,word):
for i in text:
if (i==word):
return("Word found")
else:
return("Word not found")
text = input()
word = input()
print(search(text,word))

Answer 11

Pallavi Bhardwaj thanks for this I tried my self and others too but It won't worked thanks for this 🥺💜

Answer 12

Yeahh sure I'm doing 💜😗

Answer 13

Can you share your code ?

Answer 14

def seacrh(text,word) :
if word in text :
print ('Word found')
else:
print('Word not found')
text = input()
word = input() seacrh(text,word)

Here you go

Answer 15

Check your indentation. It doesn't look right here...

Answer 16

Rapmonster
In your code, there are some syntax error. Change them. Like in the function, it must be "search", but here it's written "seacrh".

Happy coding!

Answer 17

Bpicks are the problem

Code:

def search(text,word) :
if word in text :
print ('Word found')
else:
print('Word not found')
text = input()
word = input()
search(text,word)

Still error dude

Answer 18

It say it's not defined code ran properly but then I get what we say in testing case

Answer 19

I'm trying this from last 2 days still ?🥲

Answer 20

# Here’s another variant:

print(repr(wd := input()), "is" if wd in (txt := input()) else "is not", "in" ,repr(txt))