What is the output of this code and what are the levels of debugging?

Question

#include <iostream>
using namespace std;

int main() {
int i=5;
for(;i<7;i+=4)
i=i*i;
cout<<i;

return 0;
}

Answer 1

The code flow ...

* Define int <i> with value (5)

+ Entering loop (round 1) ...

* Verify is <i> (5) < 7 (yes)
* Enter and execute loop body, <i> is squared and became 25

* After loop body executed, <i> is incremented by 4 and became 29

+ Continue loop (round 2) ...
* Verify is <i> (29) < 7 (no)
Loop terminated ...

* Print <i> (29)

Answer 2

This program would return i*i+4 which is 29...
But you are on sololearn, so why not just run it and see for yourself?

https://code.sololearn.com/cuszC2lEHy6v/?ref=app

Answer 3

Okey, here is an explanation:

// i initialized with value of 5
int i = 5;

// loop that iterates in range of 5-7
// with step of 4
for (; i<7; i+=4)
// i is squared now, making it 25
i = i*i
// this is the end of the loop so I gets
// incremented by 4 because of the
// loop step..
// as 25+4 is more than 7, loop
// does not continue

// and then just print out i
cout << i;

Answer 4

I ve run it mr Aleksei Radchenkov but i did not understand what is the process of the last answer its vague for me somehow that in the second iteration how the loop send the output like that.