Is there any command for that?

Question

"A percentage value rounded up to the nearest whole number" - from the Halloween candy task

Answer 1

Quarkom replace round() with ceil(). Here is your corrected program:

import math
houses = int(input())
housesBill= 2
percentage=(100*housesBill)/(houses)
print(math.ceil(percentage))

Answer 2

Quarkom round() does not work here because it sometimes rounds down. Since the task is to always round up, you should use the ceil() function from the math library.

Answer 3

Yeah, the round() function. For example:
print(round(80.01720))
Output:
80
Other example:
print(round(90.100, 2))
Output:
90.1
Because:
The second parameter is the amount after of . and if you don't put a second parameter, is a total number.
Any doubt ask me.

Answer 4

Tysm

Answer 5

Yes, round function. Sample:
x = round(5.765)
x will be 6

Answer 6

Ty, however sololearn still won't accept my code even if code shows good answers and my output is the same as expected one. Here is the code:

Answer 7

houses = int(input())
housesBill= 2
percentage=(100*housesBill)/(houses)
print(round(percentage))

Answer 8

Brian could u pls write how that command should look like with an input integer?

Answer 9

Brian
X=int(input())
print(ceil(X))
?

Answer 10

Thanks guys, topic ended.

Answer 11

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