What am I doing wrong with the overloading operator?

Question

The result should be a new queue, where the elements of the first queue come first, followed by the second queue's elements.

Given the Queue class, overload the + operator, so that the code in main works and successfully adds two queues.

///////////////my code

#include <iostream>
using namespace std;

class Queue {
int size;
int* queue;

public:
Queue() {
size = 0;
queue = new int[100];
}

Queue operator+(Queue &obj) {
Queue res;
res.size= this->size+obj.size;
return res;
}

void add(int data) {
queue[size] = data;
size++;
}
void remove() {
if (size == 0) {
cout << "Queue is empty"<<endl;
return;
}
else {
for (int i = 0; i < size - 1; i++) {
queue[i] = queue[i + 1];
}
size--;
}
}
void print() {
if (size == 0) {
cout << "Queue is empty"<<endl;
return;
}
for (int i = 0; i < size; i++) {
cout<<queue[i]<<" <- ";
}
cout << endl;
}

};

int main() {
Queue q1;
q1.add(42); q1.add(2); q1.add(8); q1.add(1);
Queue q2;
q2.add(3); q2.add(66); q2.add(128); q2.add(5);
Queue q3 = q1+q2;
q3.print();

return 0;
}

Answer 1

By the overloading operator you have added only new size, but forgoten to add the new elements of second queue.

Answer 2

JaScript so do I make another overloading operator?

Answer 3

No Rubayet Kamal . All is in the same function, which will return the sum.