Why do reverseString() and for() return error?

Question

I cannot find any syntax error. Yet the code does not work.
https://code.sololearn.com/caB7uzPOB5Xv/?ref=app

Answer 1

// I fixed a few lines of code

import java.util.Scanner;
class ReverseFunction {
static String reverseString(String w) {
String r="";
char[] arr = w.toCharArray();
for(int i=arr.length-1; i>=0; i--) r += arr[i];
return r;
}
}
public class ReverseCode {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String word = sc.nextLine();
System.out.println(ReverseFunction.reverseString(word));
}
}

Answer 2

Billy Beagle

Every method needs a return type.
If you don't want to return a value return type is void:
public static void yourMethod()

In your case you want to return a String:
public static String yourMethod()

Btw: Your method would return the last char of your String.

Your loop is okay, you only need to add each char to a new empty String. After the loop return this String. (See SoloProg solution)

Answer 3

//correction are in comments...

import java.util.Scanner;
class ReverseFunction {
static reverseString(String string) { //return type missing , add it
//public static void reverseString(String string){

char[] arr = string.toCharArray();
for(int i=arr.length-1;; i>=0; i++) { //uee i-- instead of i++

return arr[i]; // print value instead of returning.., use System.out.print(arr[I]); return returns to calling at first iteration. Not returns all. not prints all. you may misunderstood ' return'
}
}
}
public class ReverseCode {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String word = sc.nextLine();

System.out.println(reverseString(word));//method is in another class so call it by class name. like
// ReverseFunction.reverseString(word);

}
}

Answer 4

SoloProg Denise Roßberg Jayakrishna🇮🇳 thank you all, it works now! A nice day to all! :)