The code is showing error

Question

n = int(input())
if n in range(2,5) and n%2==0 or n>20:
print("Not Weid")
if n in range(6,20) and n%2==0 or n!=20:
print("Weid")

Answer 1

Actually your code is not proper indented after if condition u need to give some tabs your code don't have any logical errors

n = int(input())
if n in range(2,5) and n%2==0 or n>20:
print("Not Weid")
if n in range(6,20) and n%2==0 or n!=20:
print("Weid")

Answer 2

Nisha it's ok, you just didn't indent it

n = int(input())
if n in range(2,5) and n%2==0 or n>20:
print("Not Weid")
if n in range(6,20) and n%2==0 or n!=20:
print("Weid")

Answer 3

It says expected an indentad block

Answer 4

Indentation is very important in python.