what is output of code and how?

Question

int c=0
if(c)
printf("%d",c=0);
else
printf("%d",c=1);
printf("%d\n",c);

Answer 1

Well it will produce error correct code is \/

#include <stdio.h>
int main() {
int c=0;
if(c){
printf("%d",c=0);
}
else{
printf("%d",c=1);
printf("%d\n",c);
}
return 0;
}

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https://www.sololearn.com/Course/C/?ref=app

Answer 2

After correcting the missing #include and missing ; the output would be:

11

Here is why. See comments.

#include <stdio.h>
int main() {

int c=0; // initial value is 0
if(c)      // 0 is false. Skip to else.
printf("%d",c=0);
else
printf("%d",c=1); // assign 1 to c, print it
printf("%d\n",c); // print c again, 1

return 0;
}