Plz explain 7th line of code and hence the output?

Question

c++ challenge question.
https://code.sololearn.com/cu43n6fXgk38/?ref=app

Answer 1

gaurav kumar

Actually here ASCII value is subtracting not character

A character can assign to int data type but when you print that you get ASCII value.

Try this:

int a = 'a';
cout << a;

Answer 2

gaurav kumar

c = s[3] = a

On line number 7 there is ++c so now c would be b as it is increasing ASCII value of a so next character is b

++c = b

Now s[1] is b so a would be 0

Answer 3

gaurav kumar

ASCII value of a = 97
ASCII value of b = 98

So here ++c would be 98 but c is a char so it will print b

if you do

int a = 'a' then you will get cout << a; as 97

Answer 4

A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟ plz tell how we can subtract two characters.

Answer 5

char is an integer data type, we can subtract them.
in your example:
++c = s[1] = 'b'
a = ++c-s[1] = 'b' - 'b' = 98 - 98 = 0