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What sorting is wrong 🙄
https://code.sololearn.com/ctB3LrnXm3qW/?ref=app Iam try to input a array and I like to sort it ascending and descending orders Sorting is mistake in my code . check and solve it guys
9 odpowiedzi
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Provide more description of your question, give some sample input and the desired output to get more relevant answers.
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Thank you very much
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Okay 👌🆗
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#include <bits/stdc++.h>
using namespace std;
int main()
{
int arr[10],c;
cout<<"Enter the number of elements in the array \n";
cin>>c;
int b = sizeof(arr);
cout<<"leanth off array= "<<b<<endl;
int q = sizeof(arr[0]);
cout<<q<<endl;
//(1) no need n thus n value
//int n = sizeof(arr) / sizeof(arr[0]); //sizeof (arr) is the total size occupied by the array. sizeof (arr [0]) is the size of the first element in the array.
cout<<"enter the every elements of the array orderly\n";
for(int i=0;i<c;i++)
{
cin>>arr[i];
}
cout<<"The array is\n";
for(int i=0;i<c;i++)
{
cout<<arr[i]<<" "<<"\n";
}
cout<<endl;
//(2)
// sort(arr,arr+n); n is total array size you declared as you calculated. you just need to use c as array elenents you are using.. so use
sort(arr,arr+c); //sorting the array from start to end.
//cond...
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cout<<"Ascending order is \n";
for(int i=0;i<c;i++) //(3) array indexes starts from 0 so use, i=0 instead of 1 andd condition i<c;
{
cout<<arr[i]<<" ";
}
cout<<endl;
sort(arr,arr+c,greater<int>()); //(4)here same use c instead of n
cout<<"Descending order is \n";
for(int i=0;i<c;i++) //(5)same here use i=0 to c
{
cout<<arr[i]<<" ";
}
}
edit:
https://code.sololearn.com/cKASQ0bcX57b/?ref=app
+ 2
you can remove n variable because unused.
And better to use
#include<iostream>
#include<algorithm>
In place of
#include <bits/stdc++.h>
You're welcome..
edit:
https://code.sololearn.com/cKASQ0bcX57b/?ref=app
+ 2
Okay 👌
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Look at this code for reference:
This is best for dynamically storing and sorting array.
plus it sorts floats and integral values
https://code.sololearn.com/cM95l02G31pX/?ref=app