Why the answer is -1?

Question

#include <stdio.h>
#define square(x) x*x
int main() {
int i=square(4-1);
printf("%d",i);
return 0;
}

https://code.sololearn.com/cwpxqN047TC7/?ref=app

Answer 1

HamidReza , evaluate it => 4-1*4-1=> 4-4-1=> - 1.

Answer 2

thnx.

Answer 3

#include<stdio.h>
#define square(x) x*
int main()
{
int i=square(4-1);
/* It basically work as:
i=4-1*4-1
Multiplication solves first so,the above statement becomes
i=4-4-1
i=-1 */
printf("%d",i);
return 0;
}

Answer 4

Thank you TheWh¡teCat 🇧🇬

https://code.sololearn.com/cerU8AFJDS11

Answer 5

Add parenthesis for your code to work

#define square(x) (x)*(x)