Here the programme supposed to sum only the odd numbers so what is the wrong in this code ? 🤔

Question

numbers=(input())

list=[]

for n in numbers:
if n%2==0:
list.append()
else:
continue

print(sum(list))

Answer 1

Mostafa Ahmad ,

your code is slightly reworked and has the respective comments:

numbers = [int(i) for i in input().split()] # numbers has to be split and converted to int, input is done like: 1 2 3 4 5 6
lst=[] # please do not use variable names that are also used by python

for n in numbers:
if n%2==1:
lst.append(n) # append was missing an argument inside parenthesis
#else: # not required
#continue # not required

print(sum(lst))

Answer 2

If you really want the list just append it under sum += num

n = int(input())
sum = 0
for num in range(n):
if num % 2 == 0:
sum += num
print(sum)

Answer 3

The remainder of dividing an odd number by 2 is 1

Answer 4

1. numbers=int(input())
2. I have no idea about task, but in for loop should be range of something, e.g. numbers or list of numbers.
Or something like this:
numbers= int(input())
sum=0
for _ in range(numbers):
n = int(input())
if n%2: sum +=n
print(sum)

Answer 5

even it give an error ☹