Тhe result of an exam will be determined as follows։ If the score is 88 and above => excellent 40-87 => good 0-39 => fail

Question

var score = parseInt(readLine(), 10)
/*
88 and above => excellent
40-87 => good
0-39 => fail
*/
if((score >= 88) && (score>89)){
console.log("excellent")
}
else if((score>=40) && (score<88)){
console.log("good")
}
else{
((score>=0) && (score<=39))
console.log("fail")

It only fails when input 88. Please, help me

Answer 1

Remove the and part of the initial condition, its unnecessary and causing only 90+ to be excellent

Answer 2

var score = parseInt(readLine(), 10)
/*
88 and above => excellent
40-87 => good
0-39 => fail
*/
// your code goes here

if(score >=88) console.log("excellent"); else if (score >=40 && score <88) console.log("good"); else console.log("fail");

Answer 3

In first 'if' write:
...score>=88 (no need to write the second one:- score>89)

In second 'else if' write:
...score<=87

Answer 4

Thank you very much, I've removed && (score>89) and it works.

Answer 5

var score = parseInt(readLine(), 10)
/*
88 and above => excellent
40-87 => good
0-39 => fail
*/
// your code goes here
if(score >= 88){

console.log("excellent");

}else if((score >= 40)&&(score <= 87)){

console.log("good");

}else{

console.log("fail");
}

Answer 6

var score = parseInt(readLine(), 10)

if(score>=88)
{
console.log("exellent")
}
else if((score>=40) && (score<88));
{
console.log("good ");
}
else
{
console.log("fail");
}