How to add value to a list without insert () operators?

Question

https://code.sololearn.com/cOeLjXd5P3KI/?ref=app

Answer 1

Ahh, then it looks like you may actually need a deepcopy instead of a shallow copy. Something like this might be more what you're after.

from copy import deepcopy

a = [[1,2,3,4,5], [6,7,8,9,10]]

def creat_six_digits(a, value_given):

b = deepcopy(a)
c = b[0][-1];
e, f = divmod(c * value_given, 5)
b[0][-1] = e
b[0] += [f]

return b

Answer 2

You can append a list to another list using the += operator. Like;

a = [[1,2,3,5], [9,8,7,6]]
b = 4
a[1] += [b] # without insert() use

print(a)

# result should be.
# [[1,2,3,5], [9,8,7,6,4]]

To insert into the list you can use slicing of the list to the location in the list you wish to insert at;

a = [[1,2,3,5], [9,8,7,6]]
b = 4
a[0][:3] += [b] # without insert() use

print(a)

# result should be.
# [[1,2,3,4,5], [9,8,7,6]]

Answer 3

Then you can just make a shallow copy of a and operate on that for your new variable.

a = [[1,2,3,5], [9,8,7,6]]
b = 4
c = a[:] # make copy of a so a is unchanged
c[0][:3] += [b] # without insert() use

print(c)

# result should be.
# [[1,2,3,4,5], [9,8,7,6]]

Answer 4

Thiley Dorje Lama Slice assignment is all I can think of, as pointed out by ChaoticDawg

Answer 5

I need result in new variable.

Answer 6

https://code.sololearn.com/cpN5kJQKwBwU/?ref=app

Answer 7

This is the problem I couldn't solve
I need only six digits
But using operators digits keep adding in all applications