The below code is showing syntax error at line 21 where else: is given. Could anyone pls tell me what is wrong with it?

Question

def menu():
c='y'
while c=='y':
print("1.Add Record")
print("2.Update Record")
print("3.Delete Record")
print("4.Display records")
print("5.Exit")
choice=int(input("Enter your choice"))
if choice==1:
addrecord()
elif choice ==2:
updatedata()
elif choice==3:
deldata()
elif choice==4:
fetchdata()
elif choice==5:
print("Exiting")
break
else:
print ("Wrong Input")
c=input("Do you want to continue or not,press y or n")

Answer 1

#Identation error:

#Working code :

def menu():
c='y'
while c=='y':
print("1.Add Record")
print("2.Update Record")
print("3.Delete Record")
print("4.Display records")
print("5.Exit")
choice=int(input("Enter your choice"))
if choice==1:
addrecord()
elif choice ==2:
updatedata()
elif choice==3:
deldata()
elif choice==4:
fetchdata()
elif choice==5:
print("Exiting")
break
else:
print ("Wrong Input")
c=input("Do you want to continue or not,press y or n")

menu()

Answer 2

Sam https://code.sololearn.com/c9CjjfoSre8U/?ref=app