String arr[ ];

Question

In java how to finde a String array(index number) by equaling with int ?
int a=6;
if(String arr[i]==a){}

Answer 1

I am trying to catch array indexs value by entering a number
int choice =sc.nexInt();
String arr[]={"java","c","c++"};
for(int i=0;i<arr.length;i++){
If(choice==arr[i]){
System.out.print(arr[i]);
}
}

Answer 2

AB Rahman "Mamnoon"

choice is integer

And arr[i] is string then how you can compare?

How number will be equal to string?

If you want index value then compare with index like (choice == i)

If you want index then you should enter string to get index by comparing with equals method.

like (choice.equals(arr[i]))

Answer 3

AB Rahman "Mamnoon"

If you want a value on a particular index then why don't pass index value directly like this:

System.out.print(arr[choice]);

Answer 4

Scanner sc = new Scanner(System.in);
int choice = sc.nextInt(); //debug
String arr[]={"java","c","c++"};
for(int i=0;i<arr.length;i++){
if(choice==i){ //debug 🤔
System.out.print(arr[i]);
}
}

Answer 5

Scanner sc = new Scanner(System.in);
String arr[]={"java","c","c++"};
int choice =sc.nexInt();

System.out.println(arr[choice]);

Answer 6

What you want to trying to do?