algorithm and logic

Question

FYI:
For any integer value X except.x=0:
pow(x,3) / pow(x,2) /.power(x,1) = 1;
and
pow(x,3) / pow(x,2) - x = 0.

Thank you very much.

Answer 1

Does X ^ 3 refer to X raised to the power of 3, or X (bitwise)XOR 3?

Answer 2

Power or exponential, pow(int x, int y), pow(x,3);

Answer 3

And you were looking forward to check whether a given <x> qualifies the two condition? or is it something else?

I tried it in a code checking range 1 ~ 100 and each number passed both of the conditions. But I'm not sure that was what you meant to do ...

Answer 4

Yes, discrete math. Number theory of exponentiality.

Answer 5

Not sure what you are asking???

Pow(x, 3) / pow(x, 2) / pow(x, 1) == pow(x, 3) / pow(x, 3) == 1 forall integer except 0. (can't divide by 0)

Pow(x, 3) / pow(x, 2) - x == (pow(x, 3) - x*pow(x, 2)) / pow(x, 2)

But x * pow(x, 2) == pow(x, 3)

Therefore, (pow(x, 3) - x*pow(x, 2)) / pow(x, 2) == (pow(x, 3) - pow(x, 3)) / pow(x, 2) == 0 / pow(x, 2) == 0, thus true forall integer except 0

If this mathematical proof is what you are after. Perhaps you should review some algebra as it is essential for discrete maths and number theory.

Answer 6

Yes Adam McGregor. You right. I made a mistake this afternoon. This can be extended; not just only for non-negative but it acceptable to any integer value (both positive and negative ) except x=0.

Answer 7

Sololearn should revise their problem. For some positive integers values less than 25? No no no no. For each integer value from -infinity to +infinity except 0.

Answer 8

Hello friend