wats wrong in this code for finding standard deviation

Question

my_list = [180, 172, 178, 185, 190, 195, 192, 200, 210, 190]
a=(sum((x-(sum(my_list) / len(my_list)))**2 for x in my_list) / (len(my_list)-1))**0.5
print(a)

Answer 1

Ok let me try it out

Answer 2

You are missing the point..

"You need to calculate and output **how many players are in the range of one standard deviation from the mean**"

Range in standard deviation from mean is : between mean+standard deviation, mean-standard deviation

Answer 3

You seem to have your parenthesis mixed up. Try this to find the std deviation:

a = (sum((x - sum(my_list )/len(my_list))**2 for x in my_list)/len(my_list)) **0.5

#To find the range of players:

print(len([i for i in my_list if (sum(my_list)/len(my_list) - std_dev) < i < (sum(my_list)/len(my_list) + std_dev)]))

Answer 4

...(len(my_list))**0.5
print(int(a))

Answer 5

nope not working

Answer 6

#try this:

my_list = [180, 172, 178, 185, 190, 195, 192, 200, 210, 190]
a=(sum((x-(sum(my_list) / len(my_list)))**2 for x in my_list) / (len(my_list)))**0.5
print(a)

#can you see expected result?

Answer 7

Nope its not working

Answer 8

Is there asked to round the result or integer result?

Answer 9

Test case is hidden

Answer 10

Sorry could u plz elaborate cant able to catch ur point

Answer 11

Can you post full question..? Is this about find football players in range mean to standard deviation?

Answer 12

S

Answer 13

The task is to find players in range between mean±standard deviation

Find mean, standard deviation.
Then find player height in range between mean-standard deviation and mean + standard deviation and print result...

edit: again try and see this next. .

my_list = [180, 172, 178, 185, 190, 195, 192, 200, 210, 190]
mean = sum(my_list)/len(my_list)
stdv=(sum((x-(sum(my_list) / len(my_list)))**2 for x in my_list) / (len(my_list)))**0.5

print(len([i for i in my_list if mean-stdv<i< mean+stdv]))

Answer 14

a = (sum((x-sum(players)/len(players))**2 for x in players)/len(players))**0.5

This formula (a) returns the standard deviation. But, you need to calculate one standard deviation from the mean.

Add this

std_pos = sum(my_list)/len(my_list) + a
std_neg = sum(my_list)/len(my_list) - a

print(len([i for i in my_list if std_neg < i < std_pos ]))

Answer 15

import numpy as np

players = [180, 172, 178, 185, 190, 195, 192, 200, 210, 190]

ply_mean=sum(players)/len(players)

ply_std=(sum([(v-ply_mean)**2 for v in players])/len(players))**0.5

low = ply_mean-ply_std
high = ply_mean+ply_std

count=len([v for v in players if low<v<high])

print(count)

Try this