What is this code at line 6?

Question

#include <stdio.h>
#include <iostream>
using namespace std;
void update(int *a,int *b) {
int sum = *a + *b;
int absDifference = *a - *b > 0 ? *a - *b : -(*a - *b); //here what is going on??
*a = sum;
*b = absDifference;
}

int main() {
int a, b;
int *pa = &a, *pb = &b;

scanf("%d %d", &a, &b);
update(pa, pb);
printf("%d\n%d", a, b);

return 0;
}

Answer 1

https://www.sololearn.com/Discuss/2799644/?ref=app

Answer 2

It is finding the absolute value of the difference. A more readable version might look like this:

absDifference = *a - *b;
if (absDifference<0)
absDifference = -absDifference;

Answer 3

It's within the update() function.
It's has pointers a and b.
Saves their sum to variable sum
It's using ternary to do a sort of if-else assignment of absDifference variable.
Checks if a - b is positive assigns a - b, else assigns -(a -b) //negative of a negative is a positive.
Then copies sum to the address pointed to by a
Copies absDifference to the address pointed to by b
No return for that function.