Alternating order of items ( no modules )

Question

#your code goes here

#Let´s make this example without using modules ( if you want to make it with modules, it is at the end of first example )

#You are given a list of items, and need to find all the possible orders of the items.
#The output should be a list, containing all possible orders.

#Sample Input
#['a', 'b']

#Sample Output
#----->[('a', 'b'), ('b', 'a')]

#Who wish to improves mind and logic, trial so:

items = ['x', 'y']

newItems = [];

i = 0;

elements = len( items );
posiciton = elements - 1;

while ( posiciton >= i ):

newItems.append( items[ posiciton ] );
posiciton=posiciton-1;

result = ""
resultNewItems = ""
finalResult = ""
finalResultNewItems = ""

for j in items:

result += "'"+j+"', "

for k in newItems:

resultNewItems += "'"+k+"', "

resultNoComasEnd = result
resultNewItemsNoComasEnd = resultNewItems

finalResult = "[("+resultNoComasEnd+")"
finalResultNewItems = "("+resultNewItemsNoComasEnd+")]"

fixedFinalResult = finalResult.replace( finalResult[len(finalResult)-3] + " )" , ")" )
fixedFinalResultNewItems = finalResultNewItems.replace( finalResultNewItems[len(finalResultNewItems)-4] + " )" , ")" )

print( "----->" + fixedFinalResult + ", " + fixedFinalResultNewItems )

#On top, it is done with modules, right here let make it with one. Take in account, it gets code saved 50 lines off

#Easy Example:

from itertools import permutations

items = ['x', 'y']

result = list( permutations( items ) )

print( result )