Square root in python

Question

How to use ** function to get square root of number. It says String cannot be converted to float.

Answer 1

#if you not understood, see this :

num = int( input() )

sq = num ** 0.5

print(sq)

Answer 2

Jayakrishain

Good example because if you have a number to the power of a half then it will output the square root of that answer.

Answer 3

n=int(input('Enter a base : ')
m=int(input('Enter a root : ')
x= n**(1/m)
print(x)

Answer 4

Add your tried code here.

ex:
print( 25**(1/2))

Answer 5

So using the example given it would result as 5 because 25 to the power of half is 5

Answer 6

It says lousy conversion from str to float

Answer 7

Input() is accepted as string form default. So you need to convert to required type.. There convert to inter type..

Answer 8

Thanks for the help :)

Answer 9

I think its done for you ☺️

Answer 10

Import math
x = int(input())
Print(math.sqrt(x))

Answer 11

lst=[int(x) for x in input().split()]
sqrlst=[x**0.5 for x in lst]
print("Square root of numbers entered : ",*sqrlst)
###Run it once...it will help u alot

Answer 12

lst=[int(x) for x in input().split()]
sqrlst=[round(x**0.5,2) for x in lst]
print("Square root of numbers entered : ",*sqrlst)
###Run it once....if u want to fix output up to 2 decimal..

Answer 13

num = input()

sq = num ** 0.5

print(sq)

Answer 14

Acg hhc nbvxnm

Answer 15

print (x**0.5)

Answer 16

import math

Answer 17

Write a python3 function sqr( n ) that returns the square of its numeric parameter n.