Can any one correct this code?

Question

def mixx(num1,num2,num3):
if num1 > num2 and num1 >num3 and num2 >num3 :
print (list[num1 ,num2 ,num3 ])

elif num1 > num2 and num1 >num3 and num3 >num2 :
print (list[num1 ,num3 ,num2 ])
elif num2 > num1 and num2>num3 and num1 >num3:
print (list[num2 ,num1 ,num3 ])
elif num2 > num1 and num2 >num3 and num3 >num1 :
print (list [num2 ,num3 ,num1 ])
elif num3 > num2 and num3>num1 and num2 >num1 :
print (list [num3 ,num2 ,num1 ])
elif num3> num2 and num3>num1 and num1>num2 :
print (list [num3 ,num1 ,num2 ])

else :
print (num3 )
print (num2 )
print (num1 )

mixx (1,6,17)

Answer 1

What exactly are you trying to achieve with this code?

Answer 2

Are u trying to arrange the list in ascending or descending order?

Answer 3

You have some unnecessary conditions like in the first one num1>num2 and num2>num3 already mean that num1>num3 so that middle condition is logically redundant

Answer 4

You could do something like this in order to get the code to do the work for you

def mixx(a,b,c):
r = [a,b,c]
for i in range(1,3):
if r[i-1] < r[i]:
r[i-1],r[i] = r[i],r[i-1]
return r

n1 = 2
n2 = 7
n3 = 5

print(mixx(n1,n2,n3))