Javascript Problem with function

Question

function y(x){
x= x+1;
return x++;
}
console.log(y(2));

Why it's returning 3?

X= 2
Then, x= x+1 //x=3
Then, x++; // x = 4?

Help me please

Answer 1

In your function you type 5 but in comments 1, I think you make typo and meant x = x + 1

Reason why it return 3 not 4 is because of how increment work.
When you type x++ it will add 1 to x but after this line of code end.
So when you return, value is 3, but after return it will be 4 (this will never run because return exit from function)
Check my code to understand better
https://code.sololearn.com/W56Ig5vNOH7R/?ref=app

Answer 2

PanicS Thanks now I understand.🔮

Answer 3

Sachin

x++ post increment first assign then increment by 1

++x pre increment first increment by 1 then assign

So if there is ++x then x = 4

Answer 4

A͢J Thanks