What will be the output? If user enter character instead of integer?

Question

int turn=0;
while(1)
{
printf("Enter your choice for toss\n1. Head\n2. Tail\n");
scanf("%d", &turn);
if(turn==1||turn==2)
{
break;
}
else
{
printf("Invalid choice \n Please re-enter your choice.\n");
}
}

Answer 1

#include <stdio.h>

int main() {

int turn=0;

while(1)
{
printf("Enter your choice for toss\n1. Head\n2. Tail\n");
scanf("%d", &turn);
if(turn==1||turn==2)
{
printf("input Match");
break;
}
else
{
printf("Invalid choice \n Please re-enter your choice.\n");

// if input is not integer , then this will read (consume) until next next line or space or End of Input
while((turn = getc(stdin)) != EOF && turn != '\n' && turn != ' ');
// getc() reads a character
}
}

return 0;
}

// hope it helps...

Answer 2

Actually I don't know why when I'm writing the above code and inputting a character value it's going into an infinite loop

Answer 3

Oky can you please suggest me right code ..all I want to display same MSG till the user inputs the right integer value...also keep that in mind that if the user inputs character or float or double it's should display a warning message with another chance to input

Answer 4

Thanku sir😊

Answer 5

%d looks for an integer input so on no integer input, it will not take any input to turn.
I think, you may have any other specific doubt related to this ..!!?

Answer 6

Because turn will remain 0
Other than, until input 1 or 2, it's infinite loop..

Answer 7

You're welcome..