l=[1,2,3,2,2,4,5,2,5,2,4] x=2 i=0 while i<l.count(x): if x in l: l.remove(x) i=i+1 print(l)

Question

Please explain flow of this question and output

Answer 1

Irshad Ahmad

count function will count the value exist in list

So l.count(2) = 4

remove function will remove value from the list but single value not all duplicate value

remove(x) #here value x is a value.

x in l: here checking value x exist in list or not.

As we are removing value from list "l" so after every iteration value will be remove from the list and you will get new list.

while 0 < 4: //true
if 2 in l: //true
l.remove(2)

Loop will work untill the condition returns True and after each iteration value will be remove on particular index and new list will be generate.

1st iteration condition 0 < 5 is true and 2 exist in list so
l.remove(2) = [1, 3, 2, 2, 4, 5, 2, 5, 2, 4] #new list

2nd iteration 1 < 4: true and 2 exist in new list so
l.remove(2) = [1, 3, 2, 4, 5, 2, 5, 2, 4] #new list

3rd iteration 2 < 3: true and 2 exist in new list so
l.remove(2) = [1, 3, 4, 5, 2, 5, 2, 4] #new list

4th iteration 3 < 2: false so loop will be break

And new list is [1, 3, 4, 5, 2, 5, 2, 4]

Answer 2

Thanks bro got it❤️❤️❤️❤️