Solve using basic conditions of python

Question

Phone Number Validator

You are given a number input, and need to check if it is a valid phone number.
A valid phone number has exactly 8 digits and starts with 1, 8 or 9.
Output "Valid" if the number is valid and "Invalid", if it is not.

Sample Input
81239870

Sample Output
Valid

Answer 1

number = int(input())

if len(str(number))==8:
if (str(number)[0]=="1" or str(number)[0]=="8" or str(number)[0]=="9"):
print("Valid")
else:
print("Invalid")
else:
print("Invalid")

#I have tried this out and this works;)

Answer 2

And Shahram's code is working buddy

Answer 3

Use if else condition to check if length of the string is equal to 8 and check if string[0]==1 or 8 or 9
If all conditions return true print Valid else print Invalid.

Answer 4

Please send the code

Answer 5

phone = input()
if (len(phone)==8) and (phone[0]=="1" or phone[0]=="8" or phone[0]=="9"):
print('Valid')
else:
print('Invalid')

Answer 6

num = input ("Enter number: ")
if len(num) > 8:
print("Invalid")
elif num[0] != 1 or num[0] != 8 or num[0] != 9:
print("Invalid")
else:
print("Valid")

😭😭😭 I know it's long but don't worry about me, I'll be fine

Answer 7

Hey it's not working for 81234567

Answer 8

Why the rest of code are not working except yours... What's the problem in there code ?

Answer 9

In Stephen's code, you can see in the elif statement that he compared the not equal value with integers, whereas he has taken an input of string, "1","8","9"..it should be like this.